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Ufumbuzi - Tiger algebra Suluhishaji

138541.65

138541.65

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22679, 9, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 679$ , $r = 9 %$ , $n = 1$ , $t = 21$ .

$c i (22679, 9, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 679$ , $r = 9 %$ , $n = 1$ , $t = 21$ .

$P = 22679, r = 9 %, n = 1, t = 21$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 679$ , $r = 9 %$ , $n = 1$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 679$ , $r = 9 %$ , $n = 1$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 679$ , $r = 9 %$ , $n = 1$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 21$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 21, {(1 + r / n)}^{(n t)} = 6.1088077369$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{21} = 6.1088077369$

$r / n = 0.09, n t = 21, {(1 + r / n)}^{(n t)} = 6.1088077369$ .

$6.1088077369$

$r / n = 0.09, n t = 21, {(1 + r / n)}^{(n t)} = 6.1088077369$ .

3. Hesabu kiasi cha mwisho

$A = 138541.65$

$138541.65$

$22, 679 \cdot 6.1088077369 = 138541.65$ .

$138541.65$

$22, 679 \cdot 6.1088077369 = 138541.65$ .

$138541.65$

$22, 679 \cdot 6.1088077369 = 138541.65$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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