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Ufumbuzi - Tiger algebra Suluhishaji

25128.18

25128.18

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22638, 11, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 638$ , $r = 11 %$ , $n = 1$ , $t = 1$ .

$c i (22638, 11, 1, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 638$ , $r = 11 %$ , $n = 1$ , $t = 1$ .

$P = 22638, r = 11 %, n = 1, t = 1$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 638$ , $r = 11 %$ , $n = 1$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 638$ , $r = 11 %$ , $n = 1$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 638$ , $r = 11 %$ , $n = 1$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.11$

$n t = 1$

${(1 + r / n)}^{(n t)}$

$r / n = 0.11, n t = 1, {(1 + r / n)}^{(n t)} = 1.11$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.11)}^{1} = 1.11$

$r / n = 0.11, n t = 1, {(1 + r / n)}^{(n t)} = 1.11$ .

$1.11$

$r / n = 0.11, n t = 1, {(1 + r / n)}^{(n t)} = 1.11$ .

3. Hesabu kiasi cha mwisho

$A = 25128.18$

$25128.18$

$22, 638 \cdot 1.11 = 25128.18$ .

$25128.18$

$22, 638 \cdot 1.11 = 25128.18$ .

$25128.18$

$22, 638 \cdot 1.11 = 25128.18$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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