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Ufumbuzi - Tiger algebra Suluhishaji

292056.56

292056.56

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22608, 13, 4, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 608$ , $r = 13 %$ , $n = 4$ , $t = 20$ .

$c i (22608, 13, 4, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 608$ , $r = 13 %$ , $n = 4$ , $t = 20$ .

$P = 22608, r = 13 %, n = 4, t = 20$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 608$ , $r = 13 %$ , $n = 4$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 608$ , $r = 13 %$ , $n = 4$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 608$ , $r = 13 %$ , $n = 4$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0325$

$n t = 80$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0325, n t = 80, {(1 + r / n)}^{(n t)} = 12.9182839489$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0325)}^{80} = 12.9182839489$

$r / n = 0.0325, n t = 80, {(1 + r / n)}^{(n t)} = 12.9182839489$ .

$12.9182839489$

$r / n = 0.0325, n t = 80, {(1 + r / n)}^{(n t)} = 12.9182839489$ .

3. Hesabu kiasi cha mwisho

$A = 292056.56$

$292056.56$

$22, 608 \cdot 12.9182839489 = 292056.56$ .

$292056.56$

$22, 608 \cdot 12.9182839489 = 292056.56$ .

$292056.56$

$22, 608 \cdot 12.9182839489 = 292056.56$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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