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Ufumbuzi - Tiger algebra Suluhishaji

839406.15

839406.15

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22472, 13, 12, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 472$ , $r = 13 %$ , $n = 12$ , $t = 28$ .

$c i (22472, 13, 12, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 472$ , $r = 13 %$ , $n = 12$ , $t = 28$ .

$P = 22472, r = 13 %, n = 12, t = 28$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 472$ , $r = 13 %$ , $n = 12$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 472$ , $r = 13 %$ , $n = 12$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 472$ , $r = 13 %$ , $n = 12$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 336$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 336, {(1 + r / n)}^{(n t)} = 37.3534241381$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{336} = 37.3534241381$

$r / n = 0.0108333333, n t = 336, {(1 + r / n)}^{(n t)} = 37.3534241381$ .

$37.3534241381$

$r / n = 0.0108333333, n t = 336, {(1 + r / n)}^{(n t)} = 37.3534241381$ .

3. Hesabu kiasi cha mwisho

$A = 839406.15$

$839406.15$

$22, 472 \cdot 37.3534241381 = 839406.15$ .

$839406.15$

$22, 472 \cdot 37.3534241381 = 839406.15$ .

$839406.15$

$22, 472 \cdot 37.3534241381 = 839406.15$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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