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Ufumbuzi - Tiger algebra Suluhishaji

61929.22

61929.22

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22446, 7, 1, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 446$ , $r = 7 %$ , $n = 1$ , $t = 15$ .

$c i (22446, 7, 1, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 446$ , $r = 7 %$ , $n = 1$ , $t = 15$ .

$P = 22446, r = 7 %, n = 1, t = 15$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 446$ , $r = 7 %$ , $n = 1$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 446$ , $r = 7 %$ , $n = 1$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 446$ , $r = 7 %$ , $n = 1$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 15$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 15, {(1 + r / n)}^{(n t)} = 2.7590315407$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{15} = 2.7590315407$

$r / n = 0.07, n t = 15, {(1 + r / n)}^{(n t)} = 2.7590315407$ .

$2.7590315407$

$r / n = 0.07, n t = 15, {(1 + r / n)}^{(n t)} = 2.7590315407$ .

3. Hesabu kiasi cha mwisho

$A = 61929.22$

$61929.22$

$22, 446 \cdot 2.7590315407 = 61929.22$ .

$61929.22$

$22, 446 \cdot 2.7590315407 = 61929.22$ .

$61929.22$

$22, 446 \cdot 2.7590315407 = 61929.22$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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