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Ufumbuzi - Tiger algebra Suluhishaji

54762.33

54762.33

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22414, 6, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 414$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$c i (22414, 6, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 414$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$P = 22414, r = 6 %, n = 4, t = 15$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 414$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 414$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 414$ , $r = 6 %$ , $n = 4$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{60} = 2.4432197757$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

$2.4432197757$

$r / n = 0.015, n t = 60, {(1 + r / n)}^{(n t)} = 2.4432197757$ .

3. Hesabu kiasi cha mwisho

$A = 54762.33$

$54762.33$

$22, 414 \cdot 2.4432197757 = 54762.33$ .

$54762.33$

$22, 414 \cdot 2.4432197757 = 54762.33$ .

$54762.33$

$22, 414 \cdot 2.4432197757 = 54762.33$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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