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Ufumbuzi - Tiger algebra Suluhishaji

1294059.60

1294059.60

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22332, 14, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 332$ , $r = 14 %$ , $n = 2$ , $t = 30$ .

$c i (22332, 14, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 332$ , $r = 14 %$ , $n = 2$ , $t = 30$ .

$P = 22332, r = 14 %, n = 2, t = 30$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 332$ , $r = 14 %$ , $n = 2$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 332$ , $r = 14 %$ , $n = 2$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 332$ , $r = 14 %$ , $n = 2$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 60, {(1 + r / n)}^{(n t)} = 57.9464268345$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{60} = 57.9464268345$

$r / n = 0.07, n t = 60, {(1 + r / n)}^{(n t)} = 57.9464268345$ .

$57.9464268345$

$r / n = 0.07, n t = 60, {(1 + r / n)}^{(n t)} = 57.9464268345$ .

3. Hesabu kiasi cha mwisho

$A = 1294059.60$

$1294059.60$

$22, 332 \cdot 57.9464268345 = 1294059.60$ .

$1294059.60$

$22, 332 \cdot 57.9464268345 = 1294059.60$ .

$1294059.60$

$22, 332 \cdot 57.9464268345 = 1294059.60$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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