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Ufumbuzi - Tiger algebra Suluhishaji

40369.82

40369.82

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22287, 4, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 287$ , $r = 4 %$ , $n = 2$ , $t = 15$ .

$c i (22287, 4, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 287$ , $r = 4 %$ , $n = 2$ , $t = 15$ .

$P = 22287, r = 4 %, n = 2, t = 15$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 287$ , $r = 4 %$ , $n = 2$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 287$ , $r = 4 %$ , $n = 2$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 287$ , $r = 4 %$ , $n = 2$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 30$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 30, {(1 + r / n)}^{(n t)} = 1.8113615841$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{30} = 1.8113615841$

$r / n = 0.02, n t = 30, {(1 + r / n)}^{(n t)} = 1.8113615841$ .

$1.8113615841$

$r / n = 0.02, n t = 30, {(1 + r / n)}^{(n t)} = 1.8113615841$ .

3. Hesabu kiasi cha mwisho

$A = 40369.82$

$40369.82$

$22, 287 \cdot 1.8113615841 = 40369.82$ .

$40369.82$

$22, 287 \cdot 1.8113615841 = 40369.82$ .

$40369.82$

$22, 287 \cdot 1.8113615841 = 40369.82$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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