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Ufumbuzi - Tiger algebra Suluhishaji

31514.32

31514.32

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22256, 5, 4, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 256$ , $r = 5 %$ , $n = 4$ , $t = 7$ .

$c i (22256, 5, 4, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 256$ , $r = 5 %$ , $n = 4$ , $t = 7$ .

$P = 22256, r = 5 %, n = 4, t = 7$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 256$ , $r = 5 %$ , $n = 4$ , $t = 7$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 256$ , $r = 5 %$ , $n = 4$ , $t = 7$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 256$ , $r = 5 %$ , $n = 4$ , $t = 7$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 28, {(1 + r / n)}^{(n t)} = 1.4159923036$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{28} = 1.4159923036$

$r / n = 0.0125, n t = 28, {(1 + r / n)}^{(n t)} = 1.4159923036$ .

$1.4159923036$

$r / n = 0.0125, n t = 28, {(1 + r / n)}^{(n t)} = 1.4159923036$ .

3. Hesabu kiasi cha mwisho

$A = 31514.32$

$31514.32$

$22, 256 \cdot 1.4159923036 = 31514.32$ .

$31514.32$

$22, 256 \cdot 1.4159923036 = 31514.32$ .

$31514.32$

$22, 256 \cdot 1.4159923036 = 31514.32$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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