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Ufumbuzi - Tiger algebra Suluhishaji

66304.33

66304.33

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22111, 8, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 111$ , $r = 8 %$ , $n = 2$ , $t = 14$ .

$c i (22111, 8, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 111$ , $r = 8 %$ , $n = 2$ , $t = 14$ .

$P = 22111, r = 8 %, n = 2, t = 14$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 111$ , $r = 8 %$ , $n = 2$ , $t = 14$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 111$ , $r = 8 %$ , $n = 2$ , $t = 14$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 111$ , $r = 8 %$ , $n = 2$ , $t = 14$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 28, {(1 + r / n)}^{(n t)} = 2.9987033192$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{28} = 2.9987033192$

$r / n = 0.04, n t = 28, {(1 + r / n)}^{(n t)} = 2.9987033192$ .

$2.9987033192$

$r / n = 0.04, n t = 28, {(1 + r / n)}^{(n t)} = 2.9987033192$ .

3. Hesabu kiasi cha mwisho

$A = 66304.33$

$66304.33$

$22, 111 \cdot 2.9987033192 = 66304.33$ .

$66304.33$

$22, 111 \cdot 2.9987033192 = 66304.33$ .

$66304.33$

$22, 111 \cdot 2.9987033192 = 66304.33$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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