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Ufumbuzi - Tiger algebra Suluhishaji

308911.58

308911.58

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22022, 9, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 022$ , $r = 9 %$ , $n = 2$ , $t = 30$ .

$c i (22022, 9, 2, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 022$ , $r = 9 %$ , $n = 2$ , $t = 30$ .

$P = 22022, r = 9 %, n = 2, t = 30$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 022$ , $r = 9 %$ , $n = 2$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 022$ , $r = 9 %$ , $n = 2$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 022$ , $r = 9 %$ , $n = 2$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 60, {(1 + r / n)}^{(n t)} = 14.0274079289$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{60} = 14.0274079289$

$r / n = 0.045, n t = 60, {(1 + r / n)}^{(n t)} = 14.0274079289$ .

$14.0274079289$

$r / n = 0.045, n t = 60, {(1 + r / n)}^{(n t)} = 14.0274079289$ .

3. Hesabu kiasi cha mwisho

$A = 308911.58$

$308911.58$

$22, 022 \cdot 14.0274079289 = 308911.58$ .

$308911.58$

$22, 022 \cdot 14.0274079289 = 308911.58$ .

$308911.58$

$22, 022 \cdot 14.0274079289 = 308911.58$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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