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Ufumbuzi - Tiger algebra Suluhishaji

114334.72

114334.72

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22018, 8, 2, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 018$ , $r = 8 %$ , $n = 2$ , $t = 21$ .

$c i (22018, 8, 2, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 018$ , $r = 8 %$ , $n = 2$ , $t = 21$ .

$P = 22018, r = 8 %, n = 2, t = 21$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 018$ , $r = 8 %$ , $n = 2$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 018$ , $r = 8 %$ , $n = 2$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 018$ , $r = 8 %$ , $n = 2$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 42$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 42, {(1 + r / n)}^{(n t)} = 5.1927839112$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{42} = 5.1927839112$

$r / n = 0.04, n t = 42, {(1 + r / n)}^{(n t)} = 5.1927839112$ .

$5.1927839112$

$r / n = 0.04, n t = 42, {(1 + r / n)}^{(n t)} = 5.1927839112$ .

3. Hesabu kiasi cha mwisho

$A = 114334.72$

$114334.72$

$22, 018 \cdot 5.1927839112 = 114334.72$ .

$114334.72$

$22, 018 \cdot 5.1927839112 = 114334.72$ .

$114334.72$

$22, 018 \cdot 5.1927839112 = 114334.72$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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