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Ufumbuzi - Tiger algebra Suluhishaji

56059.76

56059.76

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21725, 9, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 725$ , $r = 9 %$ , $n = 1$ , $t = 11$ .

$c i (21725, 9, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 725$ , $r = 9 %$ , $n = 1$ , $t = 11$ .

$P = 21725, r = 9 %, n = 1, t = 11$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 725$ , $r = 9 %$ , $n = 1$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 725$ , $r = 9 %$ , $n = 1$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 725$ , $r = 9 %$ , $n = 1$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 11$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 11, {(1 + r / n)}^{(n t)} = 2.5804264053$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{11} = 2.5804264053$

$r / n = 0.09, n t = 11, {(1 + r / n)}^{(n t)} = 2.5804264053$ .

$2.5804264053$

$r / n = 0.09, n t = 11, {(1 + r / n)}^{(n t)} = 2.5804264053$ .

3. Hesabu kiasi cha mwisho

$A = 56059.76$

$56059.76$

$21, 725 \cdot 2.5804264053 = 56059.76$ .

$56059.76$

$21, 725 \cdot 2.5804264053 = 56059.76$ .

$56059.76$

$21, 725 \cdot 2.5804264053 = 56059.76$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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