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Ufumbuzi - Tiger algebra Suluhishaji

442348.63

442348.63

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21527, 13, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 527$ , $r = 13 %$ , $n = 2$ , $t = 24$ .

$c i (21527, 13, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 527$ , $r = 13 %$ , $n = 2$ , $t = 24$ .

$P = 21527, r = 13 %, n = 2, t = 24$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 527$ , $r = 13 %$ , $n = 2$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 527$ , $r = 13 %$ , $n = 2$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 527$ , $r = 13 %$ , $n = 2$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.065$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.065, n t = 48, {(1 + r / n)}^{(n t)} = 20.5485496076$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.065)}^{48} = 20.5485496076$

$r / n = 0.065, n t = 48, {(1 + r / n)}^{(n t)} = 20.5485496076$ .

$20.5485496076$

$r / n = 0.065, n t = 48, {(1 + r / n)}^{(n t)} = 20.5485496076$ .

3. Hesabu kiasi cha mwisho

$A = 442348.63$

$442348.63$

$21, 527 \cdot 20.5485496076 = 442348.63$ .

$442348.63$

$21, 527 \cdot 20.5485496076 = 442348.63$ .

$442348.63$

$21, 527 \cdot 20.5485496076 = 442348.63$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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