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Ufumbuzi - Tiger algebra Suluhishaji

30670.16

30670.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21474, 2, 1, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 474$ , $r = 2 %$ , $n = 1$ , $t = 18$ .

$c i (21474, 2, 1, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 474$ , $r = 2 %$ , $n = 1$ , $t = 18$ .

$P = 21474, r = 2 %, n = 1, t = 18$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 474$ , $r = 2 %$ , $n = 1$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 474$ , $r = 2 %$ , $n = 1$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 474$ , $r = 2 %$ , $n = 1$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 18$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 18, {(1 + r / n)}^{(n t)} = 1.4282462476$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{18} = 1.4282462476$

$r / n = 0.02, n t = 18, {(1 + r / n)}^{(n t)} = 1.4282462476$ .

$1.4282462476$

$r / n = 0.02, n t = 18, {(1 + r / n)}^{(n t)} = 1.4282462476$ .

3. Hesabu kiasi cha mwisho

$A = 30670.16$

$30670.16$

$21, 474 \cdot 1.4282462476 = 30670.16$ .

$30670.16$

$21, 474 \cdot 1.4282462476 = 30670.16$ .

$30670.16$

$21, 474 \cdot 1.4282462476 = 30670.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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