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Ufumbuzi - Tiger algebra Suluhishaji

144452.88

144452.88

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21472, 10, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 472$ , $r = 10 %$ , $n = 1$ , $t = 20$ .

$c i (21472, 10, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 472$ , $r = 10 %$ , $n = 1$ , $t = 20$ .

$P = 21472, r = 10 %, n = 1, t = 20$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 472$ , $r = 10 %$ , $n = 1$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 472$ , $r = 10 %$ , $n = 1$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 472$ , $r = 10 %$ , $n = 1$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.1$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.1, n t = 20, {(1 + r / n)}^{(n t)} = 6.7274999493$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.1)}^{20} = 6.7274999493$

$r / n = 0.1, n t = 20, {(1 + r / n)}^{(n t)} = 6.7274999493$ .

$6.7274999493$

$r / n = 0.1, n t = 20, {(1 + r / n)}^{(n t)} = 6.7274999493$ .

3. Hesabu kiasi cha mwisho

$A = 144452.88$

$144452.88$

$21, 472 \cdot 6.7274999493 = 144452.88$ .

$144452.88$

$21, 472 \cdot 6.7274999493 = 144452.88$ .

$144452.88$

$21, 472 \cdot 6.7274999493 = 144452.88$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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