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Ufumbuzi - Tiger algebra Suluhishaji

79445.75

79445.75

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21430, 14, 1, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 430$ , $r = 14 %$ , $n = 1$ , $t = 10$ .

$c i (21430, 14, 1, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 430$ , $r = 14 %$ , $n = 1$ , $t = 10$ .

$P = 21430, r = 14 %, n = 1, t = 10$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 430$ , $r = 14 %$ , $n = 1$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 430$ , $r = 14 %$ , $n = 1$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 430$ , $r = 14 %$ , $n = 1$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 10, {(1 + r / n)}^{(n t)} = 3.7072213141$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{10} = 3.7072213141$

$r / n = 0.14, n t = 10, {(1 + r / n)}^{(n t)} = 3.7072213141$ .

$3.7072213141$

$r / n = 0.14, n t = 10, {(1 + r / n)}^{(n t)} = 3.7072213141$ .

3. Hesabu kiasi cha mwisho

$A = 79445.75$

$79445.75$

$21, 430 \cdot 3.7072213141 = 79445.75$ .

$79445.75$

$21, 430 \cdot 3.7072213141 = 79445.75$ .

$79445.75$

$21, 430 \cdot 3.7072213141 = 79445.75$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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