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Ufumbuzi - Tiger algebra Suluhishaji

40568.04

40568.04

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21414, 4, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 414$ , $r = 4 %$ , $n = 12$ , $t = 16$ .

$c i (21414, 4, 12, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 414$ , $r = 4 %$ , $n = 12$ , $t = 16$ .

$P = 21414, r = 4 %, n = 12, t = 16$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 414$ , $r = 4 %$ , $n = 12$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 414$ , $r = 4 %$ , $n = 12$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 414$ , $r = 4 %$ , $n = 12$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0033333333$

$n t = 192$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0033333333, n t = 192, {(1 + r / n)}^{(n t)} = 1.8944635242$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0033333333)}^{192} = 1.8944635242$

$r / n = 0.0033333333, n t = 192, {(1 + r / n)}^{(n t)} = 1.8944635242$ .

$1.8944635242$

$r / n = 0.0033333333, n t = 192, {(1 + r / n)}^{(n t)} = 1.8944635242$ .

3. Hesabu kiasi cha mwisho

$A = 40568.04$

$40568.04$

$21, 414 \cdot 1.8944635242 = 40568.04$ .

$40568.04$

$21, 414 \cdot 1.8944635242 = 40568.04$ .

$40568.04$

$21, 414 \cdot 1.8944635242 = 40568.04$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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