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Ufumbuzi - Tiger algebra Suluhishaji

23044.00

23044.00

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21273, 1, 12, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 273$ , $r = 1 %$ , $n = 12$ , $t = 8$ .

$c i (21273, 1, 12, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 273$ , $r = 1 %$ , $n = 12$ , $t = 8$ .

$P = 21273, r = 1 %, n = 12, t = 8$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 273$ , $r = 1 %$ , $n = 12$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 273$ , $r = 1 %$ , $n = 12$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 273$ , $r = 1 %$ , $n = 12$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0008333333$

$n t = 96$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0008333333, n t = 96, {(1 + r / n)}^{(n t)} = 1.0832509788$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0008333333)}^{96} = 1.0832509788$

$r / n = 0.0008333333, n t = 96, {(1 + r / n)}^{(n t)} = 1.0832509788$ .

$1.0832509788$

$r / n = 0.0008333333, n t = 96, {(1 + r / n)}^{(n t)} = 1.0832509788$ .

3. Hesabu kiasi cha mwisho

$A = 23044.00$

$23044.00$

$21, 273 \cdot 1.0832509788 = 23044.00$ .

$23044.00$

$21, 273 \cdot 1.0832509788 = 23044.00$ .

$23044.00$

$21, 273 \cdot 1.0832509788 = 23044.00$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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