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Ufumbuzi - Tiger algebra Suluhishaji

98279.80

98279.80

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21171, 13, 4, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 171$ , $r = 13 %$ , $n = 4$ , $t = 12$ .

$c i (21171, 13, 4, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 171$ , $r = 13 %$ , $n = 4$ , $t = 12$ .

$P = 21171, r = 13 %, n = 4, t = 12$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 171$ , $r = 13 %$ , $n = 4$ , $t = 12$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 171$ , $r = 13 %$ , $n = 4$ , $t = 12$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 171$ , $r = 13 %$ , $n = 4$ , $t = 12$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0325$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0325, n t = 48, {(1 + r / n)}^{(n t)} = 4.6421898296$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0325)}^{48} = 4.6421898296$

$r / n = 0.0325, n t = 48, {(1 + r / n)}^{(n t)} = 4.6421898296$ .

$4.6421898296$

$r / n = 0.0325, n t = 48, {(1 + r / n)}^{(n t)} = 4.6421898296$ .

3. Hesabu kiasi cha mwisho

$A = 98279.80$

$98279.80$

$21, 171 \cdot 4.6421898296 = 98279.80$ .

$98279.80$

$21, 171 \cdot 4.6421898296 = 98279.80$ .

$98279.80$

$21, 171 \cdot 4.6421898296 = 98279.80$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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