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Ufumbuzi - Tiger algebra Suluhishaji

280857.26

280857.26

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21154, 13, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 154$ , $r = 13 %$ , $n = 12$ , $t = 20$ .

$c i (21154, 13, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 154$ , $r = 13 %$ , $n = 12$ , $t = 20$ .

$P = 21154, r = 13 %, n = 12, t = 20$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 154$ , $r = 13 %$ , $n = 12$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 154$ , $r = 13 %$ , $n = 12$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 154$ , $r = 13 %$ , $n = 12$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0108333333$

$n t = 240$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0108333333, n t = 240, {(1 + r / n)}^{(n t)} = 13.2767921555$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0108333333)}^{240} = 13.2767921555$

$r / n = 0.0108333333, n t = 240, {(1 + r / n)}^{(n t)} = 13.2767921555$ .

$13.2767921555$

$r / n = 0.0108333333, n t = 240, {(1 + r / n)}^{(n t)} = 13.2767921555$ .

3. Hesabu kiasi cha mwisho

$A = 280857.26$

$280857.26$

$21, 154 \cdot 13.2767921555 = 280857.26$ .

$280857.26$

$21, 154 \cdot 13.2767921555 = 280857.26$ .

$280857.26$

$21, 154 \cdot 13.2767921555 = 280857.26$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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