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Ufumbuzi - Tiger algebra Suluhishaji

84612.35

84612.35

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21047, 5, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 047$ , $r = 5 %$ , $n = 4$ , $t = 28$ .

$c i (21047, 5, 4, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 047$ , $r = 5 %$ , $n = 4$ , $t = 28$ .

$P = 21047, r = 5 %, n = 4, t = 28$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 047$ , $r = 5 %$ , $n = 4$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 047$ , $r = 5 %$ , $n = 4$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 047$ , $r = 5 %$ , $n = 4$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 112$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 112, {(1 + r / n)}^{(n t)} = 4.0201621588$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{112} = 4.0201621588$

$r / n = 0.0125, n t = 112, {(1 + r / n)}^{(n t)} = 4.0201621588$ .

$4.0201621588$

$r / n = 0.0125, n t = 112, {(1 + r / n)}^{(n t)} = 4.0201621588$ .

3. Hesabu kiasi cha mwisho

$A = 84612.35$

$84612.35$

$21, 047 \cdot 4.0201621588 = 84612.35$ .

$84612.35$

$21, 047 \cdot 4.0201621588 = 84612.35$ .

$84612.35$

$21, 047 \cdot 4.0201621588 = 84612.35$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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