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Ufumbuzi - Tiger algebra Suluhishaji

24402.54

24402.54

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (21023, 5, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 023$ , $r = 5 %$ , $n = 4$ , $t = 3$ .

$c i (21023, 5, 4, 3)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 023$ , $r = 5 %$ , $n = 4$ , $t = 3$ .

$P = 21023, r = 5 %, n = 4, t = 3$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 023$ , $r = 5 %$ , $n = 4$ , $t = 3$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 023$ , $r = 5 %$ , $n = 4$ , $t = 3$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 21, 023$ , $r = 5 %$ , $n = 4$ , $t = 3$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 12$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 12, {(1 + r / n)}^{(n t)} = 1.1607545177$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{12} = 1.1607545177$

$r / n = 0.0125, n t = 12, {(1 + r / n)}^{(n t)} = 1.1607545177$ .

$1.1607545177$

$r / n = 0.0125, n t = 12, {(1 + r / n)}^{(n t)} = 1.1607545177$ .

3. Hesabu kiasi cha mwisho

$A = 24402.54$

$24402.54$

$21, 023 \cdot 1.1607545177 = 24402.54$ .

$24402.54$

$21, 023 \cdot 1.1607545177 = 24402.54$ .

$24402.54$

$21, 023 \cdot 1.1607545177 = 24402.54$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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