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Ufumbuzi - Tiger algebra Suluhishaji

15060.09

15060.09

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2075, 9, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 075$ , $r = 9 %$ , $n = 1$ , $t = 23$ .

$c i (2075, 9, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 075$ , $r = 9 %$ , $n = 1$ , $t = 23$ .

$P = 2075, r = 9 %, n = 1, t = 23$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 075$ , $r = 9 %$ , $n = 1$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 075$ , $r = 9 %$ , $n = 1$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 075$ , $r = 9 %$ , $n = 1$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 23$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 23, {(1 + r / n)}^{(n t)} = 7.2578744722$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{23} = 7.2578744722$

$r / n = 0.09, n t = 23, {(1 + r / n)}^{(n t)} = 7.2578744722$ .

$7.2578744722$

$r / n = 0.09, n t = 23, {(1 + r / n)}^{(n t)} = 7.2578744722$ .

3. Hesabu kiasi cha mwisho

$A = 15060.09$

$15060.09$

$2, 075 \cdot 7.2578744722 = 15060.09$ .

$15060.09$

$2, 075 \cdot 7.2578744722 = 15060.09$ .

$15060.09$

$2, 075 \cdot 7.2578744722 = 15060.09$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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