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Ufumbuzi - Tiger algebra Suluhishaji

24192.30

24192.30

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20741, 8, 1, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 741$ , $r = 8 %$ , $n = 1$ , $t = 2$ .

$c i (20741, 8, 1, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 741$ , $r = 8 %$ , $n = 1$ , $t = 2$ .

$P = 20741, r = 8 %, n = 1, t = 2$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 741$ , $r = 8 %$ , $n = 1$ , $t = 2$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 741$ , $r = 8 %$ , $n = 1$ , $t = 2$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 741$ , $r = 8 %$ , $n = 1$ , $t = 2$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.08$

$n t = 2$

${(1 + r / n)}^{(n t)}$

$r / n = 0.08, n t = 2, {(1 + r / n)}^{(n t)} = 1.1664$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.08)}^{2} = 1.1664$

$r / n = 0.08, n t = 2, {(1 + r / n)}^{(n t)} = 1.1664$ .

$1.1664$

$r / n = 0.08, n t = 2, {(1 + r / n)}^{(n t)} = 1.1664$ .

3. Hesabu kiasi cha mwisho

$A = 24192.30$

$24192.30$

$20, 741 \cdot 1.1664 = 24192.30$ .

$24192.30$

$20, 741 \cdot 1.1664 = 24192.30$ .

$24192.30$

$20, 741 \cdot 1.1664 = 24192.30$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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