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Ufumbuzi - Tiger algebra Suluhishaji

422278.91

422278.91

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20739, 14, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 14 %$ , $n = 1$ , $t = 23$ .

$c i (20739, 14, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 14 %$ , $n = 1$ , $t = 23$ .

$P = 20739, r = 14 %, n = 1, t = 23$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 14 %$ , $n = 1$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 14 %$ , $n = 1$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 14 %$ , $n = 1$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 23$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 23, {(1 + r / n)}^{(n t)} = 20.3615849587$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{23} = 20.3615849587$

$r / n = 0.14, n t = 23, {(1 + r / n)}^{(n t)} = 20.3615849587$ .

$20.3615849587$

$r / n = 0.14, n t = 23, {(1 + r / n)}^{(n t)} = 20.3615849587$ .

3. Hesabu kiasi cha mwisho

$A = 422278.91$

$422278.91$

$20, 739 \cdot 20.3615849587 = 422278.91$ .

$422278.91$

$20, 739 \cdot 20.3615849587 = 422278.91$ .

$422278.91$

$20, 739 \cdot 20.3615849587 = 422278.91$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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