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Ufumbuzi - Tiger algebra Suluhishaji

339992.51

339992.51

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20739, 12, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 12 %$ , $n = 2$ , $t = 24$ .

$c i (20739, 12, 2, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 12 %$ , $n = 2$ , $t = 24$ .

$P = 20739, r = 12 %, n = 2, t = 24$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 12 %$ , $n = 2$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 12 %$ , $n = 2$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 739$ , $r = 12 %$ , $n = 2$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 48, {(1 + r / n)}^{(n t)} = 16.3938717293$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{48} = 16.3938717293$

$r / n = 0.06, n t = 48, {(1 + r / n)}^{(n t)} = 16.3938717293$ .

$16.3938717293$

$r / n = 0.06, n t = 48, {(1 + r / n)}^{(n t)} = 16.3938717293$ .

3. Hesabu kiasi cha mwisho

$A = 339992.51$

$339992.51$

$20, 739 \cdot 16.3938717293 = 339992.51$ .

$339992.51$

$20, 739 \cdot 16.3938717293 = 339992.51$ .

$339992.51$

$20, 739 \cdot 16.3938717293 = 339992.51$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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