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Ufumbuzi - Tiger algebra Suluhishaji

23917.59

23917.59

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20609, 3, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 609$ , $r = 3 %$ , $n = 2$ , $t = 5$ .

$c i (20609, 3, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 609$ , $r = 3 %$ , $n = 2$ , $t = 5$ .

$P = 20609, r = 3 %, n = 2, t = 5$

$\frac{3}{100} = 0.03$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 609$ , $r = 3 %$ , $n = 2$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 609$ , $r = 3 %$ , $n = 2$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 609$ , $r = 3 %$ , $n = 2$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 10, {(1 + r / n)}^{(n t)} = 1.160540825$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{10} = 1.160540825$

$r / n = 0.015, n t = 10, {(1 + r / n)}^{(n t)} = 1.160540825$ .

$1.160540825$

$r / n = 0.015, n t = 10, {(1 + r / n)}^{(n t)} = 1.160540825$ .

3. Hesabu kiasi cha mwisho

$A = 23917.59$

$23917.59$

$20, 609 \cdot 1.160540825 = 23917.59$ .

$23917.59$

$20, 609 \cdot 1.160540825 = 23917.59$ .

$23917.59$

$20, 609 \cdot 1.160540825 = 23917.59$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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