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Ufumbuzi - Tiger algebra Suluhishaji

56407.19

56407.19

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20594, 13, 2, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 594$ , $r = 13 %$ , $n = 2$ , $t = 8$ .

$c i (20594, 13, 2, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 594$ , $r = 13 %$ , $n = 2$ , $t = 8$ .

$P = 20594, r = 13 %, n = 2, t = 8$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 594$ , $r = 13 %$ , $n = 2$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 594$ , $r = 13 %$ , $n = 2$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 594$ , $r = 13 %$ , $n = 2$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.065$

$n t = 16$

${(1 + r / n)}^{(n t)}$

$r / n = 0.065, n t = 16, {(1 + r / n)}^{(n t)} = 2.739010672$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.065)}^{16} = 2.739010672$

$r / n = 0.065, n t = 16, {(1 + r / n)}^{(n t)} = 2.739010672$ .

$2.739010672$

$r / n = 0.065, n t = 16, {(1 + r / n)}^{(n t)} = 2.739010672$ .

3. Hesabu kiasi cha mwisho

$A = 56407.19$

$56407.19$

$20, 594 \cdot 2.739010672 = 56407.19$ .

$56407.19$

$20, 594 \cdot 2.739010672 = 56407.19$ .

$56407.19$

$20, 594 \cdot 2.739010672 = 56407.19$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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