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Ufumbuzi - Tiger algebra Suluhishaji

230575.16

230575.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20484, 9, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 484$ , $r = 9 %$ , $n = 12$ , $t = 27$ .

$c i (20484, 9, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 484$ , $r = 9 %$ , $n = 12$ , $t = 27$ .

$P = 20484, r = 9 %, n = 12, t = 27$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 484$ , $r = 9 %$ , $n = 12$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 484$ , $r = 9 %$ , $n = 12$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 484$ , $r = 9 %$ , $n = 12$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0075$

$n t = 324$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0075, n t = 324, {(1 + r / n)}^{(n t)} = 11.2563544337$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0075)}^{324} = 11.2563544337$

$r / n = 0.0075, n t = 324, {(1 + r / n)}^{(n t)} = 11.2563544337$ .

$11.2563544337$

$r / n = 0.0075, n t = 324, {(1 + r / n)}^{(n t)} = 11.2563544337$ .

3. Hesabu kiasi cha mwisho

$A = 230575.16$

$230575.16$

$20, 484 \cdot 11.2563544337 = 230575.16$ .

$230575.16$

$20, 484 \cdot 11.2563544337 = 230575.16$ .

$230575.16$

$20, 484 \cdot 11.2563544337 = 230575.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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