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Ufumbuzi - Tiger algebra Suluhishaji

119426.80

119426.80

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20402, 15, 4, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 402$ , $r = 15 %$ , $n = 4$ , $t = 12$ .

$c i (20402, 15, 4, 12)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 402$ , $r = 15 %$ , $n = 4$ , $t = 12$ .

$P = 20402, r = 15 %, n = 4, t = 12$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 402$ , $r = 15 %$ , $n = 4$ , $t = 12$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 402$ , $r = 15 %$ , $n = 4$ , $t = 12$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 402$ , $r = 15 %$ , $n = 4$ , $t = 12$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0375$

$n t = 48$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0375, n t = 48, {(1 + r / n)}^{(n t)} = 5.8536810923$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0375)}^{48} = 5.8536810923$

$r / n = 0.0375, n t = 48, {(1 + r / n)}^{(n t)} = 5.8536810923$ .

$5.8536810923$

$r / n = 0.0375, n t = 48, {(1 + r / n)}^{(n t)} = 5.8536810923$ .

3. Hesabu kiasi cha mwisho

$A = 119426.80$

$119426.80$

$20, 402 \cdot 5.8536810923 = 119426.80$ .

$119426.80$

$20, 402 \cdot 5.8536810923 = 119426.80$ .

$119426.80$

$20, 402 \cdot 5.8536810923 = 119426.80$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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