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Ufumbuzi - Tiger algebra Suluhishaji

82196.41

82196.41

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20352, 7, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 352$ , $r = 7 %$ , $n = 12$ , $t = 20$ .

$c i (20352, 7, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 352$ , $r = 7 %$ , $n = 12$ , $t = 20$ .

$P = 20352, r = 7 %, n = 12, t = 20$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 352$ , $r = 7 %$ , $n = 12$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 352$ , $r = 7 %$ , $n = 12$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 352$ , $r = 7 %$ , $n = 12$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0058333333$

$n t = 240$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0058333333, n t = 240, {(1 + r / n)}^{(n t)} = 4.038738849$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0058333333)}^{240} = 4.038738849$

$r / n = 0.0058333333, n t = 240, {(1 + r / n)}^{(n t)} = 4.038738849$ .

$4.038738849$

$r / n = 0.0058333333, n t = 240, {(1 + r / n)}^{(n t)} = 4.038738849$ .

3. Hesabu kiasi cha mwisho

$A = 82196.41$

$82196.41$

$20, 352 \cdot 4.038738849 = 82196.41$ .

$82196.41$

$20, 352 \cdot 4.038738849 = 82196.41$ .

$82196.41$

$20, 352 \cdot 4.038738849 = 82196.41$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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