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Ufumbuzi - Tiger algebra Suluhishaji

232408.68

232408.68

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20344, 14, 2, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 344$ , $r = 14 %$ , $n = 2$ , $t = 18$ .

$c i (20344, 14, 2, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 344$ , $r = 14 %$ , $n = 2$ , $t = 18$ .

$P = 20344, r = 14 %, n = 2, t = 18$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 344$ , $r = 14 %$ , $n = 2$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 344$ , $r = 14 %$ , $n = 2$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 344$ , $r = 14 %$ , $n = 2$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 36$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 36, {(1 + r / n)}^{(n t)} = 11.4239421885$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{36} = 11.4239421885$

$r / n = 0.07, n t = 36, {(1 + r / n)}^{(n t)} = 11.4239421885$ .

$11.4239421885$

$r / n = 0.07, n t = 36, {(1 + r / n)}^{(n t)} = 11.4239421885$ .

3. Hesabu kiasi cha mwisho

$A = 232408.68$

$232408.68$

$20, 344 \cdot 11.4239421885 = 232408.68$ .

$232408.68$

$20, 344 \cdot 11.4239421885 = 232408.68$ .

$232408.68$

$20, 344 \cdot 11.4239421885 = 232408.68$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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