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Ufumbuzi - Tiger algebra Suluhishaji

16016.16

16016.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2033, 14, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 033$ , $r = 14 %$ , $n = 4$ , $t = 15$ .

$c i (2033, 14, 4, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 033$ , $r = 14 %$ , $n = 4$ , $t = 15$ .

$P = 2033, r = 14 %, n = 4, t = 15$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 033$ , $r = 14 %$ , $n = 4$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 033$ , $r = 14 %$ , $n = 4$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 033$ , $r = 14 %$ , $n = 4$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.035$

$n t = 60$

${(1 + r / n)}^{(n t)}$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.035)}^{60} = 7.8780909008$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

$7.8780909008$

$r / n = 0.035, n t = 60, {(1 + r / n)}^{(n t)} = 7.8780909008$ .

3. Hesabu kiasi cha mwisho

$A = 16016.16$

$16016.16$

$2, 033 \cdot 7.8780909008 = 16016.16$ .

$16016.16$

$2, 033 \cdot 7.8780909008 = 16016.16$ .

$16016.16$

$2, 033 \cdot 7.8780909008 = 16016.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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