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Ufumbuzi - Tiger algebra Suluhishaji

45304.22

45304.22

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2030, 11, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 030$ , $r = 11 %$ , $n = 2$ , $t = 29$ .

$c i (2030, 11, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 030$ , $r = 11 %$ , $n = 2$ , $t = 29$ .

$P = 2030, r = 11 %, n = 2, t = 29$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 030$ , $r = 11 %$ , $n = 2$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 030$ , $r = 11 %$ , $n = 2$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 030$ , $r = 11 %$ , $n = 2$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 58$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 58, {(1 + r / n)}^{(n t)} = 22.3173517622$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{58} = 22.3173517622$

$r / n = 0.055, n t = 58, {(1 + r / n)}^{(n t)} = 22.3173517622$ .

$22.3173517622$

$r / n = 0.055, n t = 58, {(1 + r / n)}^{(n t)} = 22.3173517622$ .

3. Hesabu kiasi cha mwisho

$A = 45304.22$

$45304.22$

$2, 030 \cdot 22.3173517622 = 45304.22$ .

$45304.22$

$2, 030 \cdot 22.3173517622 = 45304.22$ .

$45304.22$

$2, 030 \cdot 22.3173517622 = 45304.22$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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