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Ufumbuzi - Tiger algebra Suluhishaji

43309.47

43309.47

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20280, 4, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 280$ , $r = 4 %$ , $n = 12$ , $t = 19$ .

$c i (20280, 4, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 280$ , $r = 4 %$ , $n = 12$ , $t = 19$ .

$P = 20280, r = 4 %, n = 12, t = 19$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 280$ , $r = 4 %$ , $n = 12$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 280$ , $r = 4 %$ , $n = 12$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 280$ , $r = 4 %$ , $n = 12$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0033333333$

$n t = 228$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0033333333, n t = 228, {(1 + r / n)}^{(n t)} = 2.1355754482$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0033333333)}^{228} = 2.1355754482$

$r / n = 0.0033333333, n t = 228, {(1 + r / n)}^{(n t)} = 2.1355754482$ .

$2.1355754482$

$r / n = 0.0033333333, n t = 228, {(1 + r / n)}^{(n t)} = 2.1355754482$ .

3. Hesabu kiasi cha mwisho

$A = 43309.47$

$43309.47$

$20, 280 \cdot 2.1355754482 = 43309.47$ .

$43309.47$

$20, 280 \cdot 2.1355754482 = 43309.47$ .

$43309.47$

$20, 280 \cdot 2.1355754482 = 43309.47$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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