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Ufumbuzi - Tiger algebra Suluhishaji

232374.59

232374.59

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20166, 13, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 166$ , $r = 13 %$ , $n = 1$ , $t = 20$ .

$c i (20166, 13, 1, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 166$ , $r = 13 %$ , $n = 1$ , $t = 20$ .

$P = 20166, r = 13 %, n = 1, t = 20$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 166$ , $r = 13 %$ , $n = 1$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 166$ , $r = 13 %$ , $n = 1$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 166$ , $r = 13 %$ , $n = 1$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.13$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.13, n t = 20, {(1 + r / n)}^{(n t)} = 11.5230877647$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.13)}^{20} = 11.5230877647$

$r / n = 0.13, n t = 20, {(1 + r / n)}^{(n t)} = 11.5230877647$ .

$11.5230877647$

$r / n = 0.13, n t = 20, {(1 + r / n)}^{(n t)} = 11.5230877647$ .

3. Hesabu kiasi cha mwisho

$A = 232374.59$

$232374.59$

$20, 166 \cdot 11.5230877647 = 232374.59$ .

$232374.59$

$20, 166 \cdot 11.5230877647 = 232374.59$ .

$232374.59$

$20, 166 \cdot 11.5230877647 = 232374.59$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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