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Ufumbuzi - Tiger algebra Suluhishaji

23516.38

23516.38

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20071, 2, 1, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 071$ , $r = 2 %$ , $n = 1$ , $t = 8$ .

$c i (20071, 2, 1, 8)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 071$ , $r = 2 %$ , $n = 1$ , $t = 8$ .

$P = 20071, r = 2 %, n = 1, t = 8$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 071$ , $r = 2 %$ , $n = 1$ , $t = 8$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 071$ , $r = 2 %$ , $n = 1$ , $t = 8$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 071$ , $r = 2 %$ , $n = 1$ , $t = 8$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 8$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 8, {(1 + r / n)}^{(n t)} = 1.171659381$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{8} = 1.171659381$

$r / n = 0.02, n t = 8, {(1 + r / n)}^{(n t)} = 1.171659381$ .

$1.171659381$

$r / n = 0.02, n t = 8, {(1 + r / n)}^{(n t)} = 1.171659381$ .

3. Hesabu kiasi cha mwisho

$A = 23516.38$

$23516.38$

$20, 071 \cdot 1.171659381 = 23516.38$ .

$23516.38$

$20, 071 \cdot 1.171659381 = 23516.38$ .

$23516.38$

$20, 071 \cdot 1.171659381 = 23516.38$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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