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Ufumbuzi - Tiger algebra Suluhishaji

48655.57

48655.57

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (20002, 5, 2, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 002$ , $r = 5 %$ , $n = 2$ , $t = 18$ .

$c i (20002, 5, 2, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 002$ , $r = 5 %$ , $n = 2$ , $t = 18$ .

$P = 20002, r = 5 %, n = 2, t = 18$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 002$ , $r = 5 %$ , $n = 2$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 002$ , $r = 5 %$ , $n = 2$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 20, 002$ , $r = 5 %$ , $n = 2$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.025$

$n t = 36$

${(1 + r / n)}^{(n t)}$

$r / n = 0.025, n t = 36, {(1 + r / n)}^{(n t)} = 2.4325353157$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.025)}^{36} = 2.4325353157$

$r / n = 0.025, n t = 36, {(1 + r / n)}^{(n t)} = 2.4325353157$ .

$2.4325353157$

$r / n = 0.025, n t = 36, {(1 + r / n)}^{(n t)} = 2.4325353157$ .

3. Hesabu kiasi cha mwisho

$A = 48655.57$

$48655.57$

$20, 002 \cdot 2.4325353157 = 48655.57$ .

$48655.57$

$20, 002 \cdot 2.4325353157 = 48655.57$ .

$48655.57$

$20, 002 \cdot 2.4325353157 = 48655.57$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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