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Ufumbuzi - Tiger algebra Suluhishaji

94559.35

94559.35

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19947, 7, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 947$ , $r = 7 %$ , $n = 1$ , $t = 23$ .

$c i (19947, 7, 1, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 947$ , $r = 7 %$ , $n = 1$ , $t = 23$ .

$P = 19947, r = 7 %, n = 1, t = 23$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 947$ , $r = 7 %$ , $n = 1$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 947$ , $r = 7 %$ , $n = 1$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 947$ , $r = 7 %$ , $n = 1$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 23$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 23, {(1 + r / n)}^{(n t)} = 4.740529863$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{23} = 4.740529863$

$r / n = 0.07, n t = 23, {(1 + r / n)}^{(n t)} = 4.740529863$ .

$4.740529863$

$r / n = 0.07, n t = 23, {(1 + r / n)}^{(n t)} = 4.740529863$ .

3. Hesabu kiasi cha mwisho

$A = 94559.35$

$94559.35$

$19, 947 \cdot 4.740529863 = 94559.35$ .

$94559.35$

$19, 947 \cdot 4.740529863 = 94559.35$ .

$94559.35$

$19, 947 \cdot 4.740529863 = 94559.35$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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