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Ufumbuzi - Tiger algebra Suluhishaji

119819.80

119819.80

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19724, 8, 2, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 724$ , $r = 8 %$ , $n = 2$ , $t = 23$ .

$c i (19724, 8, 2, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 724$ , $r = 8 %$ , $n = 2$ , $t = 23$ .

$P = 19724, r = 8 %, n = 2, t = 23$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 724$ , $r = 8 %$ , $n = 2$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 724$ , $r = 8 %$ , $n = 2$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 724$ , $r = 8 %$ , $n = 2$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 46$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 46, {(1 + r / n)}^{(n t)} = 6.0748227087$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{46} = 6.0748227087$

$r / n = 0.04, n t = 46, {(1 + r / n)}^{(n t)} = 6.0748227087$ .

$6.0748227087$

$r / n = 0.04, n t = 46, {(1 + r / n)}^{(n t)} = 6.0748227087$ .

3. Hesabu kiasi cha mwisho

$A = 119819.80$

$119819.80$

$19, 724 \cdot 6.0748227087 = 119819.80$ .

$119819.80$

$19, 724 \cdot 6.0748227087 = 119819.80$ .

$119819.80$

$19, 724 \cdot 6.0748227087 = 119819.80$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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