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Ufumbuzi - Tiger algebra Suluhishaji

2712.16

2712.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (1971, 2, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 971$ , $r = 2 %$ , $n = 4$ , $t = 16$ .

$c i (1971, 2, 4, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 971$ , $r = 2 %$ , $n = 4$ , $t = 16$ .

$P = 1971, r = 2 %, n = 4, t = 16$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 971$ , $r = 2 %$ , $n = 4$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 971$ , $r = 2 %$ , $n = 4$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 1, 971$ , $r = 2 %$ , $n = 4$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 64$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 64, {(1 + r / n)}^{(n t)} = 1.3760301584$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{64} = 1.3760301584$

$r / n = 0.005, n t = 64, {(1 + r / n)}^{(n t)} = 1.3760301584$ .

$1.3760301584$

$r / n = 0.005, n t = 64, {(1 + r / n)}^{(n t)} = 1.3760301584$ .

3. Hesabu kiasi cha mwisho

$A = 2712.16$

$2712.16$

$1, 971 \cdot 1.3760301584 = 2712.16$ .

$2712.16$

$1, 971 \cdot 1.3760301584 = 2712.16$ .

$2712.16$

$1, 971 \cdot 1.3760301584 = 2712.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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