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Ufumbuzi - Tiger algebra Suluhishaji

60287.28

60287.28

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19607, 6, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 607$ , $r = 6 %$ , $n = 2$ , $t = 19$ .

$c i (19607, 6, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 607$ , $r = 6 %$ , $n = 2$ , $t = 19$ .

$P = 19607, r = 6 %, n = 2, t = 19$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 607$ , $r = 6 %$ , $n = 2$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 607$ , $r = 6 %$ , $n = 2$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 607$ , $r = 6 %$ , $n = 2$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 38$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 38, {(1 + r / n)}^{(n t)} = 3.0747834782$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{38} = 3.0747834782$

$r / n = 0.03, n t = 38, {(1 + r / n)}^{(n t)} = 3.0747834782$ .

$3.0747834782$

$r / n = 0.03, n t = 38, {(1 + r / n)}^{(n t)} = 3.0747834782$ .

3. Hesabu kiasi cha mwisho

$A = 60287.28$

$60287.28$

$19, 607 \cdot 3.0747834782 = 60287.28$ .

$60287.28$

$19, 607 \cdot 3.0747834782 = 60287.28$ .

$60287.28$

$19, 607 \cdot 3.0747834782 = 60287.28$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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