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Ufumbuzi - Tiger algebra Suluhishaji

258600.32

258600.32

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19491, 9, 1, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 9 %$ , $n = 1$ , $t = 30$ .

$c i (19491, 9, 1, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 9 %$ , $n = 1$ , $t = 30$ .

$P = 19491, r = 9 %, n = 1, t = 30$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 9 %$ , $n = 1$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 9 %$ , $n = 1$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 9 %$ , $n = 1$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.09$

$n t = 30$

${(1 + r / n)}^{(n t)}$

$r / n = 0.09, n t = 30, {(1 + r / n)}^{(n t)} = 13.2676784691$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.09)}^{30} = 13.2676784691$

$r / n = 0.09, n t = 30, {(1 + r / n)}^{(n t)} = 13.2676784691$ .

$13.2676784691$

$r / n = 0.09, n t = 30, {(1 + r / n)}^{(n t)} = 13.2676784691$ .

3. Hesabu kiasi cha mwisho

$A = 258600.32$

$258600.32$

$19, 491 \cdot 13.2676784691 = 258600.32$ .

$258600.32$

$19, 491 \cdot 13.2676784691 = 258600.32$ .

$258600.32$

$19, 491 \cdot 13.2676784691 = 258600.32$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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