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Ufumbuzi - Tiger algebra Suluhishaji

103071.42

103071.42

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19491, 7, 4, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 7 %$ , $n = 4$ , $t = 24$ .

$c i (19491, 7, 4, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 7 %$ , $n = 4$ , $t = 24$ .

$P = 19491, r = 7 %, n = 4, t = 24$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 7 %$ , $n = 4$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 7 %$ , $n = 4$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 491$ , $r = 7 %$ , $n = 4$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0175$

$n t = 96$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0175, n t = 96, {(1 + r / n)}^{(n t)} = 5.2881542933$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0175)}^{96} = 5.2881542933$

$r / n = 0.0175, n t = 96, {(1 + r / n)}^{(n t)} = 5.2881542933$ .

$5.2881542933$

$r / n = 0.0175, n t = 96, {(1 + r / n)}^{(n t)} = 5.2881542933$ .

3. Hesabu kiasi cha mwisho

$A = 103071.42$

$103071.42$

$19, 491 \cdot 5.2881542933 = 103071.42$ .

$103071.42$

$19, 491 \cdot 5.2881542933 = 103071.42$ .

$103071.42$

$19, 491 \cdot 5.2881542933 = 103071.42$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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