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Ufumbuzi - Tiger algebra Suluhishaji

39399.62

39399.62

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19382, 12, 4, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 382$ , $r = 12 %$ , $n = 4$ , $t = 6$ .

$c i (19382, 12, 4, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 382$ , $r = 12 %$ , $n = 4$ , $t = 6$ .

$P = 19382, r = 12 %, n = 4, t = 6$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 382$ , $r = 12 %$ , $n = 4$ , $t = 6$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 382$ , $r = 12 %$ , $n = 4$ , $t = 6$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 382$ , $r = 12 %$ , $n = 4$ , $t = 6$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 24, {(1 + r / n)}^{(n t)} = 2.0327941065$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{24} = 2.0327941065$

$r / n = 0.03, n t = 24, {(1 + r / n)}^{(n t)} = 2.0327941065$ .

$2.0327941065$

$r / n = 0.03, n t = 24, {(1 + r / n)}^{(n t)} = 2.0327941065$ .

3. Hesabu kiasi cha mwisho

$A = 39399.62$

$39399.62$

$19, 382 \cdot 2.0327941065 = 39399.62$ .

$39399.62$

$19, 382 \cdot 2.0327941065 = 39399.62$ .

$39399.62$

$19, 382 \cdot 2.0327941065 = 39399.62$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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