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Ufumbuzi - Tiger algebra Suluhishaji

37030.96

37030.96

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19171, 6, 12, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 171$ , $r = 6 %$ , $n = 12$ , $t = 11$ .

$c i (19171, 6, 12, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 171$ , $r = 6 %$ , $n = 12$ , $t = 11$ .

$P = 19171, r = 6 %, n = 12, t = 11$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 171$ , $r = 6 %$ , $n = 12$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 171$ , $r = 6 %$ , $n = 12$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 171$ , $r = 6 %$ , $n = 12$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 132$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 132, {(1 + r / n)}^{(n t)} = 1.9316131435$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{132} = 1.9316131435$

$r / n = 0.005, n t = 132, {(1 + r / n)}^{(n t)} = 1.9316131435$ .

$1.9316131435$

$r / n = 0.005, n t = 132, {(1 + r / n)}^{(n t)} = 1.9316131435$ .

3. Hesabu kiasi cha mwisho

$A = 37030.96$

$37030.96$

$19, 171 \cdot 1.9316131435 = 37030.96$ .

$37030.96$

$19, 171 \cdot 1.9316131435 = 37030.96$ .

$37030.96$

$19, 171 \cdot 1.9316131435 = 37030.96$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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