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Ufumbuzi - Tiger algebra Suluhishaji

21153.00

21153.00

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19144, 5, 12, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 144$ , $r = 5 %$ , $n = 12$ , $t = 2$ .

$c i (19144, 5, 12, 2)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 144$ , $r = 5 %$ , $n = 12$ , $t = 2$ .

$P = 19144, r = 5 %, n = 12, t = 2$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 144$ , $r = 5 %$ , $n = 12$ , $t = 2$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 144$ , $r = 5 %$ , $n = 12$ , $t = 2$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 144$ , $r = 5 %$ , $n = 12$ , $t = 2$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0041666667$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0041666667, n t = 24, {(1 + r / n)}^{(n t)} = 1.1049413356$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0041666667)}^{24} = 1.1049413356$

$r / n = 0.0041666667, n t = 24, {(1 + r / n)}^{(n t)} = 1.1049413356$ .

$1.1049413356$

$r / n = 0.0041666667, n t = 24, {(1 + r / n)}^{(n t)} = 1.1049413356$ .

3. Hesabu kiasi cha mwisho

$A = 21153.00$

$21153.00$

$19, 144 \cdot 1.1049413356 = 21153.00$ .

$21153.00$

$19, 144 \cdot 1.1049413356 = 21153.00$ .

$21153.00$

$19, 144 \cdot 1.1049413356 = 21153.00$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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