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Ufumbuzi - Tiger algebra Suluhishaji

136871.71

136871.71

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (19069, 11, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 069$ , $r = 11 %$ , $n = 12$ , $t = 18$ .

$c i (19069, 11, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 069$ , $r = 11 %$ , $n = 12$ , $t = 18$ .

$P = 19069, r = 11 %, n = 12, t = 18$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 069$ , $r = 11 %$ , $n = 12$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 069$ , $r = 11 %$ , $n = 12$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 19, 069$ , $r = 11 %$ , $n = 12$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0091666667$

$n t = 216$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0091666667, n t = 216, {(1 + r / n)}^{(n t)} = 7.1777077688$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0091666667)}^{216} = 7.1777077688$

$r / n = 0.0091666667, n t = 216, {(1 + r / n)}^{(n t)} = 7.1777077688$ .

$7.1777077688$

$r / n = 0.0091666667, n t = 216, {(1 + r / n)}^{(n t)} = 7.1777077688$ .

3. Hesabu kiasi cha mwisho

$A = 136871.71$

$136871.71$

$19, 069 \cdot 7.1777077688 = 136871.71$ .

$136871.71$

$19, 069 \cdot 7.1777077688 = 136871.71$ .

$136871.71$

$19, 069 \cdot 7.1777077688 = 136871.71$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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