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Ufumbuzi - Tiger algebra Suluhishaji

21249.56

21249.56

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (18869, 2, 1, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 869$ , $r = 2 %$ , $n = 1$ , $t = 6$ .

$c i (18869, 2, 1, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 869$ , $r = 2 %$ , $n = 1$ , $t = 6$ .

$P = 18869, r = 2 %, n = 1, t = 6$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 869$ , $r = 2 %$ , $n = 1$ , $t = 6$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 869$ , $r = 2 %$ , $n = 1$ , $t = 6$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 18, 869$ , $r = 2 %$ , $n = 1$ , $t = 6$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.02$

$n t = 6$

${(1 + r / n)}^{(n t)}$

$r / n = 0.02, n t = 6, {(1 + r / n)}^{(n t)} = 1.1261624193$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.02)}^{6} = 1.1261624193$

$r / n = 0.02, n t = 6, {(1 + r / n)}^{(n t)} = 1.1261624193$ .

$1.1261624193$

$r / n = 0.02, n t = 6, {(1 + r / n)}^{(n t)} = 1.1261624193$ .

3. Hesabu kiasi cha mwisho

$A = 21249.56$

$21249.56$

$18, 869 \cdot 1.1261624193 = 21249.56$ .

$21249.56$

$18, 869 \cdot 1.1261624193 = 21249.56$ .

$21249.56$

$18, 869 \cdot 1.1261624193 = 21249.56$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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